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Welcome to this collection of Class 9 Physics Chapter 7 – Motion numericals with answers. This page includes solved numerical problems based on the NCERT syllabus, covering key topics like equations of motion, acceleration, uniform and non-uniform motion, and circular motion. A PDF worksheet is also available for download. These motion numerical questions are designed to help CBSE and ICSE students practice, revise, and score better in exams.

Formula used
motion chapter class 9 numericals with answers pdf

Question 1
A train accelerates from 36 km/h to 54 km/h in 10 sec.
(i) Acceleration
(ii) The distance travelled by car.

Answer

a. Acceleration is given by
$a = \frac$
$\Delta v = 54 -36 = 18 km/hr =\frac {18 \times 1000}{3600} m/s= 5 m/s$
So a=.5 m/s²
b. Distance is given by
$S = ut + \frac{1}{2}a{t^2}$
Now u=36 km/hr =10m/s
$s=10 \times 10 + \frac {1}{2} \times .5 \times 10^2$
So s=125m

Question 2
A body whose speed is constant
(a) Must be accelerated
(b) Might be accelerated
(c) Has a constant velocity
(d) Cannot be accelerated.

Answer

might be accelerated

Question 3
A truck travelling at 54 km/h is slow down to 36 km/h in 10 sec. Find the retardation

Answer

Here u=54 km/h =15 m/s ,v=36 km/h=10 m/s
Acceleration is given by
$a = \frac$
$a = \frac {10 -15}{10} =- .5$
So a=-.5 m/s²
Negative sign implies retardation

Question 4
A particle is moving in a circle of diameter 20 m. What is its distance and as per the table given below

S.no	Rounds	Displacement	Distance
1	1
2	1.5
3	2
4	2.5

Answer

After every round, particle comes to it starting position. So displacement at full rounds will be zero

S.no	Rounds	Displacement	Distance
1	1	0	$20\pi $
2	1.5	20 m	$30\pi $
3	2	0	$40\pi $
4	2.5	20m	$50\pi $

Question 5
A scooter travelling at 10 m/s speed up to 20 m/s in 4 sec. Find the acceleration of scooter.

Answer

Acceleration is given by
$a = \frac$
$ a = \frac {20 -10}{4} = \frac {10}{4}=2.5$
So a=2.5 m/s²

Question 6
A train starts from rest and accelerate uniformly at the rate of 5 m/s² for 5 sec. Calculate the velocity of train in 5 sec.

Answer

Here u=0 ,a= 5m/s² ,t= 5 sec,v=?
Now $ v=u+at$
$v= 0 + 5 \times 5 =25$ m/s

Question 7
A object moves with uniform positive acceleration. Its velocity-time graph will be
(a) A straight line parallel to the time axis
(b) A straight line inclined at an obtuse angle to the time axis
(c) A straight line inclined at an acute angle to the time axis
(d) None of these.

Answer

Answer is (c)

Question 8
The maximum speed of a train is 90 km/h. It takes 10 hours to cover a distance of 500 km. Find the ratio of its average speed to maximum speed?

Answer

$ \text {Average speed}= \frac {\text {total distance}}{time} =\frac {500}{10}=50$ km/hr
Ratio of average speed to maximum speed= 50:90=5:9

Question 9
A car start from rest and acquire a velocity of 54 km/h in 2 sec. Find
(i) the acceleration
(ii) distance travelled by car assume motion of car is uniform?

Answer

u=0, v=54 km/h=15 m/s ,t=2 sec
a) Acceleration is given by
$a = \frac$
$a = \frac {15-0}{2}$ So a=7.5 m/s²
b) Distance is given by
$S = ut + \frac{1}{2}a{t^2}$
$s= 0 \times 2 + \frac{1}{2} \times 7.5 \times 4$
s=15m

Question 10
An object dropped from a cliff falls with a constant acceleration of 10 m/s². Find its speed 5 s after it was dropped.

Answer

$v=u+at$
$u = 0$
$v = 10 \times 5 = 50m/s$

Question 11
A ball is thrown upwards and it goes to the height 100 m and comes down
1) What is the net displacement?
2) What is the net distance?

Answer

As it comes down to the initial point
Net displacement is zero
Net distance=200 m

Practice questions on motion

Question 12
Two cars A and B race each other. The Car A ran for 2 minute at a speed of 7.5 km/h, slept for 56 minute and again ran for 2 minute at a speed of 7.5 km/h. find the average speed of the car A in the race.

Answer

We know that
$Distance = speed \times time$
Distance travelled in first 2 minute = $\frac {7.5 \times 2}{60}$ = 0.25 km

Distance travelled in last 2 minute = $\frac {7.5 \times 2}{60}$= 0.25 km

Total distance = .25+.25 = 0.5 km
Total time = 2+2+56 = 60 minute = 1 hr

Average speed = 0.5/1
= 0.5 km/hr

Question 13
Anand leaves his house at 8.30 A.M for his school. The school is 2 km away and classes start at 9.00 A.M. If he walks at a speed of 3 km/h for the first kilometre, at what speed should he walk the second kilometre to reach just in time?

Answer

$speed =\frac {distance}{time}$
or
$time= \frac {distance}{speed}$
For travelling 1 km with 3 km/hr,
Time taken = 1/3 hr = 20 min
Now he has to reach school in 30 min,So he has cover another 1 km in = 30 -20 =10 min= 1/6 hr
So speed should = distance /time= 1/(1/6) = 6 km/hr

Question 14
An object moves along a straight line with an acceleration of 2 m/s². If its initial speed is 10 m/s, what will be its speed 2 s later?

Answer

u=10 m/s,t=2 s, a=2 m/s²
$v=u+at$
$v= 10 + 2 \times 2 =14$ m/s

Question 15
A bullet hits a Sand box with a velocity of 20 m/s and penetrates it up to a distance of 6 cm. Find the deceleration of the bullet in the sand box.

Answer

We are given the following information:
Initial velocity, $u = 20 \, \text{m/s}$
Distance traveled, $d = 6 \, \text{cm} = 0.06 \, \text{m}$
We can use the equation of motion: \[v^2 = u^2 + 2ad\] Since the bullet comes to rest ($v = 0 \, \text{m/s}$), we have: \[0 = u^2 + 2ad\] Solving for deceleration ($a$): \[2ad = -u^2\] \[a = \frac\] Substituting the given values: \[a = \frac{{-(20 \, \text{m/s})^2}}{{2 \cdot 0.06 \, \text{m}}}\] \[a = -\frac{{400 \, \text{m}^2/\text{s}^2}}{{0.12 \, \text{m}}}\] \[a = -3333.33 \, \text{m/s}^2 \, \text{(rounded to two decimal places)}\] Therefore, the deceleration of the bullet in the sand box is approximately $-3333.33 \, \text{m/s}^2$.

Question 16
A particle experiences constant acceleration for 20 seconds after starting from rest. If it travels a distance D₁ in the first 10 seconds and distance D₂ in the next 10 seconds then,
(a) D₂ = D₁
(b) D₂ = 2D₁
(c) D₂ = 3D₁
(d) D₂ = 4D₁

Answer

(c)

Question 17
The velocity -time graph of SUV is given below. The mass of the SUV is 1000 kg.
Numerical Questions and answers on Motion for Class 9 physics

a. What is the distance travelled by the SUV is first 2 seconds?
b. What is the braking force at the end of 5 seconds to bring the SUV to a stop within one seconds?

Answer

a. The distance travelled by the SUV is first 2 seconds = Area of $\Delta ABE$
$= \frac {1}{2} \times AE \times BE$
$=\frac {1}{2} \times 2 \times 15= 15m$
b. Acceleration will be given by the slope of the line CD
$a= \frac {0 -15}{6-5} = -15 m/s^2$
Now mass of the SUV =1000 Kg
Braking Force will be
$F=ma = 1000 \times -15 =-15000 N$

Question 18
An electron moving with a velocity of $5 \times 10^3 m/s$ enters into a uniform electric field and acquires a uniform acceleration of $10^3 m/s^2$ in the direction of initial velocity.
i. Find out the time in which electron velocity will be doubled.?
ii. How much distance electron would cover in this time.?

Answer

Given $u= 5 \times 10^3 m/s$ , $a=10^3 m/s^2$, $v=2u =10^4$ m/s
i.Using $v=u+at$
$10^4 = 5 \times 10^3 + 10^3 t$
or
t=5 sec
ii. Using $s=ut+ \frac {1}{2}at^2$
$s = 5 \times 10^3 \times 5 + \frac {1}{2} \times 10^3 \times 5^2$
$=37.5 \times 10^3 m$

Question 19
A train 100 m long is moving with the velocity of 72 km/hr. Find the time it takes to cross the bridge which is 2 km long?

Answer

Given Lenght of Train = 100m , velocity = 72 km/hr = 20 m/s, Lenght of the Bridge =2 Km.
Total distance covered by the train to fully pass the bridge = 2000 + 100 = 2100 m
So, time taken
$ time = \frac {distance}{velocity} = \frac {2100}{20} =105 sec$

Question 20
An artificial satellite is moving in a circular orbit of radius 42.250 km (approx). Calculate its linear velocity if takes 24 hour to revolve around earth.?

Answer

Given r =42.250 km , T= 24 hour
Linear velocity in circular motion is given by
$v = \frac {2 \pi r}{T} = \frac {2 \times 3.14 \times 42.250}{24} = 11.05 km/hr$

Question 21
The velocity-time graph shows the motion of a cyclist. Find
(i) its acceleration
(ii) its velocity
(iii) the distance covered by the cyclist in 15 seconds
Numerical Questions and answers on Motion for Class 9 physics

Answer

(i) We can see from the graph that velocity is not changing So,acceleration is equal to zero.
(ii) By Reading the graph, velocity = 20 m/s
(iii) Distance covered in 15 seconds, $s = u \times t = 20 \times 15 = 300$ m

Question 22
An object starting from rest travels 20 m in first 2 s and 160 m in next 4 s.What will be the velocity after 7 s from the start.

Answer

Here u=0, s=20 m ,t=2 sec
$S = ut + \frac{1}{2}a{t^2}$
$20= 0 + \frac {1}{2} a \times 4$
$a=10 m/s^2$
Now Velocity at the end of 2 sec
$v=u+at$
$v=10 \times 2=20$ m/s
Now Checking the motion for next 4 sec, let assume acceleration be $a_1$ as we are not sure about the motion in second part
Here u=20 m/s ,s=160 m ,t=4 sec
$S = ut + \frac{1}{2}a{t^2}$
$160 = 20 \times 4 + \frac {1}{2} a_1 \times 16 $
$a_1 = 10 m/s^2$
So acceleration is constant in both the motion.
Now we can easily calculate velocity as
u=0, t= 7sec , a=10m/s²
$v=u+at$
$v= 0 + 10 \times 7= 70 m/s$

Question 23
An object travels 20 m in 2 s and then another 16 m in 2 s. What is the average speed of the object?

Answer

Total distance travelled by the object =20 m + 16 m = 36 m
Total time taken = 2 s + 2 s = 4 s
$\text {Average Speed} = \frac {\text {total Distance travelled}}{\text {total time taken }}$
$\text {Average Speed} = \frac {36}{4} = 9$ m/s

Question 24
The distance moved and the magnitude of displacement are equal in ?
(a) The earth is revolving around the Sun
(b) Object moving in circular path
(c) The pendulum is moving to and fro
(d) Object moving on straight road

Answer

(d) only.
Distance and displacement in all other cases

Question 25
Stopping distance of vehicles : When brakes are applied to a moving vehicle, the distance it travels before stopping is called stopping distance. It is an important factor for road safety and depends on the initial velocity ($v_0$) and the braking capacity, or deceleration, ?a that is caused by the braking. A car travelling at speed 72km/hr suddenly applies the brake with the deceleration of 5m/s². Find the stopping distance of the car

Answer

Here u=72 km/hr = $\frac {72 \times 1000}{3600} m/s= 20$ m/s , v=0
a= -5 m/s²
Now using the relation
$v^2 = u^2 + 2as$
$0 = (20)^2 + 2 \times (-5) \times s$
$s= 40 m$

Summary

This numericals of motion class 9 with answers is prepared keeping in mind the latest syllabus of CBSE . This has been designed in a way to improve the academic performance of the students. If you find mistakes , please do provide the feedback on the mail. You can download this as PDF also
Download Numerical Motion Problems and Solution worksheet as pdf

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Q: Is it safe to download Paro web series from Filmyzilla? A: No, downloading from Filmyzilla or similar platforms may pose risks, including copyright infringement and malware exposure.

Q: Where can I stream Paro web series? A: You can stream Paro on official streaming platforms, such as Amazon Prime Video, Netflix, or Hotstar, or subscription-based services like Zee5 or ALTBalaji.

Q: What are the benefits of streaming Paro on legitimate platforms? A: Streaming on legitimate platforms ensures a safe viewing experience, supports the creators, and provides high-quality content with minimal risks.

The Rise of Paro Web Series: A Comprehensive Guide to Downloading and Streaming

In recent years, the world of Indian entertainment has witnessed a significant shift towards web series, with numerous platforms offering a wide range of content to cater to diverse tastes. One such popular web series that has gained immense attention is the Paro web series. If you're looking for a way to download or stream the Paro web series, you've likely come across the term "Filmyzilla link." In this article, we'll explore everything you need to know about the Paro web series, its download and streaming options, and the Filmyzilla link.

What is the Paro Web Series?

The Paro web series is a popular Indian web series that revolves around the life of a young woman named Paro. The show explores themes of love, relationships, and self-discovery, making it a relatable and engaging watch for audiences. With its well-crafted storylines, talented cast, and high production values, the Paro web series has quickly gained a massive following.

Why is the Paro Web Series So Popular?

The Paro web series has become a sensation among Indian audiences, and its popularity can be attributed to several factors:

Downloading and Streaming the Paro Web Series

If you're interested in watching the Paro web series, you may have come across various platforms offering downloads and streams. One such platform is Filmyzilla, which has gained notoriety for providing pirated copies of movies and web series.

What is Filmyzilla?

Filmyzilla is a notorious website that provides pirated copies of movies, web series, and TV shows. The site has been operating for several years, and despite efforts to shut it down, it continues to evade authorities and provide illicit content to users.

Filmyzilla Link for Paro Web Series Download

We must emphasize that downloading or streaming content from Filmyzilla or similar websites is illegal and unethical. Moreover, these websites often pose a significant risk to your device's security and can compromise your personal data.

Instead of opting for Filmyzilla, we recommend exploring legitimate platforms that offer the Paro web series for download or streaming. Some popular options include:

How to Watch the Paro Web Series Legally

To watch the Paro web series legally, follow these steps:

Conclusion

The Paro web series has captured the hearts of Indian audiences with its engaging storyline, talented cast, and high production values. While it may be tempting to opt for a Filmyzilla link to download the series, we strongly advise against it. Instead, explore legitimate platforms that offer the show for streaming or download. Not only will you be supporting the creators and respecting intellectual property rights, but you'll also ensure your device's security and safety.

FAQs

By choosing to watch the Paro web series through legitimate platforms, you'll be supporting the creators and contributing to the growth of the Indian entertainment industry.

Instead of opting for illegal downloads, consider these alternatives:

While I understand the temptation to look for easy and free access to content like the Paro web series, it's crucial to prioritize legal and safe methods. Not only does this support the creators, but it also ensures your safety from potential digital threats. If you're unable to find the series through legal channels, consider reaching out to the creators or distributors to suggest where you'd like to see their content available.

I can’t help with locating or providing downloads or links to pirated content (Filmyzilla and similar sites). I can, however, help with any of the following:

Which of these would you like?

Feature: "Safe and Easy Access to Paro Web Series" Filmyzilla Link: What You Need to Know Filmyzilla

Description: Get instant access to the Paro web series with a simple and secure download process. Our feature provides a hassle-free way to stream or download the Paro web series without compromising on quality or safety.

Key Benefits:

Additional Features:

How it Works:

Disclaimer: We do not host or provide any copyrighted content. Our feature only provides access to publicly available content on Filmyzilla. Users are advised to ensure they have the necessary permissions or rights to access and download the content.

Paro Web Series Download: A Guide to Accessing the Popular Show

The Paro web series has gained immense popularity among audiences for its captivating storyline, strong characters, and exceptional production quality. If you're looking to download the series, you might have come across the term "Filmyzilla" in your search. Here's what you need to know:

What is Paro Web Series?

Paro is a Bengali web series that premiered on a popular streaming platform. The show revolves around the life of a young woman named Paro, who navigates love, relationships, and family dynamics in a contemporary Indian setting. With its relatable themes and engaging narrative, Paro has become a favorite among viewers.

What is Filmyzilla?

Filmyzilla is a notorious website known for leaking copyrighted content, including movies, TV shows, and web series. The site often provides links to download or stream pirated versions of popular releases, including the Paro web series.

Risks of Downloading from Filmyzilla

While Filmyzilla might seem like an easy way to access the Paro web series, there are significant risks involved:

Alternatives to Filmyzilla

Instead of risking your device and personal data, consider these alternative options:

Conclusion

While Filmyzilla might seem like a convenient option for downloading the Paro web series, the risks involved outweigh any perceived benefits. Opt for legitimate streaming platforms or official websites to access the show, ensuring a high-quality viewing experience while supporting the creators.

Searching for a "Filmyzilla download link" for the Paro web series

leads to illegal piracy platforms that distribute copyrighted content without permission. Using such sites is against the law in India under the Copyright Act of 1957

, which prohibits the unauthorized reproduction and distribution of films and shows. Additionally, these sites often host malicious software that can harm your device.

For a safe and high-quality viewing experience, you should use the official streaming platforms where the series is licensed. Official Platforms to Watch "Paro"

Depending on the specific version or season you are looking for, the series is available on the following legitimate services: Paro': A Tale of Deceit and Bride Trafficking on Atrangii

The Rise of Paro Web Series: A Comprehensive Guide to Downloading and Streaming

In recent years, the world of Indian entertainment has witnessed a significant shift towards web series, with numerous platforms offering a wide range of content. One such popular web series that has gained immense attention is Paro. If you're looking to download or stream Paro web series, you might have come across the term "Filmyzilla link." In this article, we'll explore everything you need to know about Paro web series, its download links, and the implications of using platforms like Filmyzilla.

What is Paro Web Series?

Paro is a popular Indian web series that revolves around the life of a young woman named Paro, who navigates through the complexities of relationships, family, and societal expectations. The series explores themes of love, loss, and self-discovery, making it relatable to a wide audience.

Why is Paro Web Series Trending?

The Paro web series has gained a massive following due to its engaging storyline, well-developed characters, and exceptional production quality. The show features a talented cast, including actresses like Neena Gupta and Ayesha Kaduskar, who bring depth and nuance to their characters.

Downloading Paro Web Series: The Filmyzilla Link

Filmyzilla is a notorious website known for providing pirated copies of movies, TV shows, and web series. If you're searching for a Paro web series download Filmyzilla link, you might be tempted to use the platform. However, we must emphasize that using such websites is not only illegal but also poses significant risks to your device and personal data.

Risks Associated with Filmyzilla and Pirated Content

Legal Alternatives for Streaming Paro Web Series

Instead of using Filmyzilla or other pirated content websites, consider exploring legitimate platforms that offer Paro web series streaming. Some popular options include:

How to Stream Paro Web Series Legally

To stream Paro web series legally, follow these steps:

Conclusion

While the temptation to use Filmyzilla links for downloading Paro web series might be strong, it's essential to prioritize your safety and security by opting for legitimate platforms. By choosing to stream Paro web series legally, you're not only supporting the creators but also ensuring a high-quality viewing experience.

FAQs

By making informed choices and choosing legitimate platforms, you can enjoy your favorite web series while supporting the creators and respecting intellectual property rights.

The Paro web series (2021) is an original crime drama starring Leena Jumani that explores the dark realities of bride trafficking. For a safe and high-quality viewing experience, you should avoid third-party piracy sites like Filmyzilla, which distribute copyrighted content illegally and often host malicious links. Official Streaming Platforms

You can watch the series legally on the following official platforms: Ullu App: The primary original home of the series.

Atrangii: Available for streaming on the Atrangii official site.

OTTplay: You can access episodes through the OTTplay platform.

VI Movies and TV: Currently listed as available for streaming for subscribers. Series Details Release Date: May 18, 2021. Lead Cast: Leena Jumani as Paro, Kundan Kumar as Sanju.

Plot: The story follows a young woman named Paro who is forced into a marriage by her mother to escape physical abuse, only to find herself trapped in a brutal bride trafficking racket. Episodes: 7 episodes, each approximately 20 minutes long. Paro (TV Series 2021) - IMDb

May 18, 2021 (India) India. Language. Hindi. Insite India. Ullu App. Paro': A Tale of Deceit and Bride Trafficking on Atrangii

Paro Full Web Series Watch Online On OTTplay. Open in App. Home»Shows»Paro. Paro Season 1 - watch full episodes streaming online

I understand you're looking for information on downloading the Paro web series, specifically through Filmyzilla. However, I must emphasize the importance of accessing content through legal and official channels to support creators and adhere to copyright laws.

That being said, here's a general overview and guidance on how to approach this:

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