42 Exam Rank 03 Direct
This is the building block of all sorting algorithms in this exam.
void swap(int *a, int *b)
int temp = *a;
*a = *b;
*b = temp;
The logic can be broken down into a simple state machine within a loop. 42 Exam Rank 03
Exam Rank 03 represents a critical milestone in the 42 Network curriculum. It serves as the gateway from the elementary "Piscine" knowledge (C basics) to the core curriculum. Unlike Rank 02, which focuses on rigid syntax and simple logic, Rank 03 requires the student to demonstrate proficiency in standard library recreation, memory management, and logic flow. This paper analyzes the structure of the exam, outlines the necessary theoretical knowledge, and provides a strategic approach to solving the quintessential Rank 03 problem: ft_printf. This is the building block of all sorting
#include <stdarg.h>
#include <unistd.h>
int ft_printf(const char *format, ...)
va_list args;
int count = 0;
int i = 0;
va_start(args, format);
while (format[i])
if (format[i] == '%')
i++;
if (format[i] == 's')
count += ft_print_str(va_arg(args, char *));
else if (format[i] == 'd')
count += ft_print_nbr(va_arg(args, int));
// ... handle other cases ...
else
write(1, &format[i], 1);
count++;
i++;
va_end(args);
return (count);
A common reason for failure is ignoring the return value. ft_printf returns the count of printed characters. If you return 0 or garbage, you will fail the grade, even if the output looks correct on the screen. The logic can be broken down into a
